(x+4)^2-5=20

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Solution for (x+4)^2-5=20 equation: 



(x+4)^2-5=20

We move all terms to the left:

(x+4)^2-5-(20)=0

We add all the numbers together, and all the variables

(x+4)^2-25=0

We move all terms containing x to the left, all other terms to the right

(x+4)^2=25

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